SopaXorzTaker
SopaXorzTaker
2 / 0
29th Jan 2015
29th Jan 2015
Hello! This save contains an encrypted uncommon word, who decodes it is a awesome person!

Comments

  • SopaXorzTaker
    SopaXorzTaker
    27th Jul 2016
    and yup, did I make a typo?
  • SopaXorzTaker
    SopaXorzTaker
    27th Jul 2016
    gunpowderTR - A=0, Z=25
  • gunpowderTR
    gunpowderTR
    15th Jul 2016
    there 2 metl ctype after first meaning you made a typo.. when you couldnt even dechiper your own code i did it xD
  • gunpowderTR
    gunpowderTR
    15th Jul 2016
    oh you already rote what you said, but theres a problem, if you ceaser cipher qnndmadqf with +25 you get rooenberg
  • gunpowderTR
    gunpowderTR
    15th Jul 2016
    q, n, n, d, m, a, d, q, f
  • gunpowderTR
    gunpowderTR
    15th Jul 2016
    17, 14, 14, 4, 13, 1, 4, 17, 6
  • gunpowderTR
    gunpowderTR
    15th Jul 2016
    to get the ctype: sim.partProperty([id of the pixel],"ctype")
  • SopaXorzTaker
    SopaXorzTaker
    20th Dec 2015
    Source code was related to elements' ctype values, which are numeric, you were supposed to look for the IDs of the elements
  • SopaXorzTaker
    SopaXorzTaker
    20th Dec 2015
    Plex, it is "Rosenberg" - A=0...Z=25
  • Plex
    Plex
    23rd Sep 2015
    I'm stumped. I'm guessing its a 9 letter word, though.... (If the answer is "sourcecode", I'm going to tear out my hair.)