Evaporating Liquids
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It is possible to evaporate oil or water at "room temp" (22°C) and very low pressure, which is nice in first place, but if you, lets say evaporate half of a given amount of either water or oil, the remainder of the liquid should be colder than 22°, but its exactly the same.
Basicly what I am asking for is that when you turn a liquid into a gas, it should "cost some energy", meaning, if a pixel of oil turns into a pixel of gas, it should cool adjecent pixels down by ~0.01° maybe more, maybe less i havent given much thought to that.
It would be pretty awsome to get this implemented in one of the future builds.
so long, floridarofl. -
that is not correct with physics.... when a pressure system is low and something evaporates it is because it's boiling point goes down due to the lowered vapor pressure, it actually wouldn't cost energy to evaporate anything.
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triclops200:it actually wouldn't cost energy to evaporate anything.
Oh but it does. ^^
How do you think, your refrigerator works?
Ok, the energy doesnt disappear ofcourse, it gets transfered to the gas molecule (=reads: pixel). -
your refrigerator works on the basis that when the liquid is a higher pressure it has all of its temperature concentrated and added together, this allows the surrounding gas to whisk the energy out of the pipe and into the surroundings.
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Heat loss from evaporation only occurs under the boiling point. If you boil a pot of water you don't expect the water in the pot to get colder do you?
If, however, you leave the pot outside and notice the water level lowering then yes, a few molecules are evaporating taking the energy they needed to evaporate from the pot causing the overall pot to (very slightly) cool.
This effect would be difficult to simulate in the game though and would have little use. -
triclops200
you should really look up refridgerator on wikipedia.
