I'm not sure I understand what you mean. I'm confused.
Whitout that line of code, pressure works as one might expect it to work (i.e. equalized pressure in the room, whatever the shape of that room is).
At the opposite, with that line of code enabled, I cannot have the expected behavior from the pressure.
Majca
As Lockheedmartin said it, the question was about the why, not the what. That being said, you should not presume what is too hard or not for others to understand... Know that you are a genius compare to some... as well as the opposite ;).
Considering I disabled the decay, I'll keep that potential instability in mind.
Thanks for the info.